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13301323210319 is a prime number
BaseRepresentation
bin1100000110001111010010…
…1001010001111001001111
31202002121001002021121100012
43001203310221101321033
53220412102220212234
644142313222423435
72541663121544054
oct301436451217117
952077032247305
1013301323210319
114269072207541
1215a9a76291b7b
1375640398a6c1
1433db04bab02b
15180ee80bd0ce
hexc18f4a51e4f

13301323210319 has 2 divisors, whose sum is σ = 13301323210320. Its totient is φ = 13301323210318.

The previous prime is 13301323210289. The next prime is 13301323210349. The reversal of 13301323210319 is 91301232310331.

13301323210319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13301323210289) and next prime (13301323210349).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13301323210319 is a prime.

It is a super-4 number, since 4×133013232103194 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13301323210349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650661605159 + 6650661605160.

It is an arithmetic number, because the mean of its divisors is an integer number (6650661605160).

Almost surely, 213301323210319 is an apocalyptic number.

13301323210319 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301323210319 is an equidigital number, since it uses as much as digits as its factorization.

13301323210319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 32.

The spelling of 13301323210319 in words is "thirteen trillion, three hundred one billion, three hundred twenty-three million, two hundred ten thousand, three hundred nineteen".