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1330133320303 = 9798311357513
BaseRepresentation
bin10011010110110010000…
…111111100001001101111
311201011022021111201200021
4103112302013330021233
5133243103112222203
62455015501143011
7165045641450224
oct23266207741157
94634267451607
101330133320303
11473119645797
12195956b5aa67
139857ac9b398
14485435b994b
15248ee5d65bd
hex135b21fc26f

1330133320303 has 4 divisors (see below), whose sum is σ = 1330135657648. Its totient is φ = 1330130982960.

The previous prime is 1330133320249. The next prime is 1330133320309. The reversal of 1330133320303 is 3030233310331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1330133320303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330133320309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 301075 + ... + 1658587.

It is an arithmetic number, because the mean of its divisors is an integer number (332533914412).

Almost surely, 21330133320303 is an apocalyptic number.

1330133320303 is a deficient number, since it is larger than the sum of its proper divisors (2337345).

1330133320303 is an equidigital number, since it uses as much as digits as its factorization.

1330133320303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2337344.

The product of its (nonzero) digits is 4374, while the sum is 25.

Adding to 1330133320303 its reverse (3030233310331), we get a palindrome (4360366630634).

The spelling of 1330133320303 in words is "one trillion, three hundred thirty billion, one hundred thirty-three million, three hundred twenty thousand, three hundred three".

Divisors: 1 979831 1357513 1330133320303