Base | Representation |
---|---|
bin | 1100000110001111100100… |
… | …1110101101011011100101 |
3 | 1202002121020110000121002110 |
4 | 3001203321032231123211 |
5 | 3220412231413200201 |
6 | 44142325011231233 |
7 | 2541665044424352 |
oct | 301437116553345 |
9 | 52077213017073 |
10 | 13301400131301 |
11 | 42691016753a7 |
12 | 15a9a97ba8519 |
13 | 7564168b0489 |
14 | 33db110b1629 |
15 | 180eeec146d6 |
hex | c18f93ad6e5 |
13301400131301 has 4 divisors (see below), whose sum is σ = 17735200175072. Its totient is φ = 8867600087532.
The previous prime is 13301400131293. The next prime is 13301400131309. The reversal of 13301400131301 is 10313100410331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (13301400131293) and next prime (13301400131309).
It is not a de Polignac number, because 13301400131301 - 23 = 13301400131293 is a prime.
It is a super-3 number, since 3×133014001313013 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301400131309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2216900021881 + ... + 2216900021886.
It is an arithmetic number, because the mean of its divisors is an integer number (4433800043768).
Almost surely, 213301400131301 is an apocalyptic number.
It is an amenable number.
13301400131301 is a deficient number, since it is larger than the sum of its proper divisors (4433800043771).
13301400131301 is an equidigital number, since it uses as much as digits as its factorization.
13301400131301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4433800043770.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 13301400131301 its reverse (10313100410331), we get a palindrome (23614500541632).
The spelling of 13301400131301 in words is "thirteen trillion, three hundred one billion, four hundred million, one hundred thirty-one thousand, three hundred one".
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