Base | Representation |
---|---|
bin | 11110001111100111000010… |
… | …010100000100101111001011 |
3 | 122102222000122111010011202020 |
4 | 132033213002110010233023 |
5 | 114413300340132411021 |
6 | 1150521500205135523 |
7 | 40005644311023600 |
oct | 3617470224045713 |
9 | 572860574104666 |
10 | 133014102232011 |
11 | 39422a67048600 |
12 | 12b0303585a5a3 |
13 | 592b239939670 |
14 | 24bbcb9d806a7 |
15 | 105a006db67c6 |
hex | 78f9c2504bcb |
133014102232011 has 72 divisors (see below), whose sum is σ = 244211524420752. Its totient is φ = 63782985974400.
The previous prime is 133014102231931. The next prime is 133014102232019. The reversal of 133014102232011 is 110232201410331.
It is not a de Polignac number, because 133014102232011 - 29 = 133014102231499 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133014102232019) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 287390460 + ... + 287852921.
It is an arithmetic number, because the mean of its divisors is an integer number (3391826728066).
Almost surely, 2133014102232011 is an apocalyptic number.
133014102232011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133014102232011 is a deficient number, since it is larger than the sum of its proper divisors (111197422188741).
133014102232011 is a wasteful number, since it uses less digits than its factorization.
133014102232011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 575243433 (or 575243415 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 133014102232011 its reverse (110232201410331), we get a palindrome (243246303642342).
The spelling of 133014102232011 in words is "one hundred thirty-three trillion, fourteen billion, one hundred two million, two hundred thirty-two thousand, eleven".
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