Base | Representation |
---|---|
bin | 10011010110110100000… |
… | …110001000110001011111 |
3 | 11201011101120202110102121 |
4 | 103112310012020301133 |
5 | 133243140044332033 |
6 | 2455023042203411 |
7 | 165046522602565 |
oct | 23266406106137 |
9 | 4634346673377 |
10 | 1330166402143 |
11 | 473136290657 |
12 | 195966053567 |
13 | 98584ab2037 |
14 | 48547b4ba35 |
15 | 2490246d62d |
hex | 135b4188c5f |
1330166402143 has 4 divisors (see below), whose sum is σ = 1408411484640. Its totient is φ = 1251921319648.
The previous prime is 1330166402141. The next prime is 1330166402153. The reversal of 1330166402143 is 3412046610331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330166402143 - 21 = 1330166402141 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1330166402099 and 1330166402108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330166402141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39122541223 + ... + 39122541256.
It is an arithmetic number, because the mean of its divisors is an integer number (352102871160).
Almost surely, 21330166402143 is an apocalyptic number.
1330166402143 is a deficient number, since it is larger than the sum of its proper divisors (78245082497).
1330166402143 is an equidigital number, since it uses as much as digits as its factorization.
1330166402143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78245082496.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 1330166402143 in words is "one trillion, three hundred thirty billion, one hundred sixty-six million, four hundred two thousand, one hundred forty-three".
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