Base | Representation |
---|---|
bin | 1100000110010000110100… |
… | …0010001100010111010000 |
3 | 1202002122002121020022102221 |
4 | 3001210031002030113100 |
5 | 3220413421443110243 |
6 | 44142422000550424 |
7 | 2542006220546521 |
oct | 301441502142720 |
9 | 52078077208387 |
10 | 13301732394448 |
11 | 4269262185643 |
12 | 15a9b6b322414 |
13 | 75646a6963a4 |
14 | 33db43282848 |
15 | 18101de97bed |
hex | c190d08c5d0 |
13301732394448 has 10 divisors (see below), whose sum is σ = 25772106514274. Its totient is φ = 6650866197216.
The previous prime is 13301732394413. The next prime is 13301732394463. The reversal of 13301732394448 is 84449323710331.
It can be written as a sum of positive squares in only one way, i.e., 10662628175424 + 2639104219024 = 3265368^2 + 1624532^2 .
It is a super-2 number, since 2×133017323944482 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13301732394395 and 13301732394404.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 415679137311 + ... + 415679137342.
Almost surely, 213301732394448 is an apocalyptic number.
It is an amenable number.
13301732394448 is a deficient number, since it is larger than the sum of its proper divisors (12470374119826).
13301732394448 is an equidigital number, since it uses as much as digits as its factorization.
13301732394448 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 831358274661 (or 831358274655 counting only the distinct ones).
The product of its (nonzero) digits is 5225472, while the sum is 52.
The spelling of 13301732394448 in words is "thirteen trillion, three hundred one billion, seven hundred thirty-two million, three hundred ninety-four thousand, four hundred forty-eight".
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