13302030041113 has 4 divisors (see below), whose sum is σ = 14511305499408. Its totient is φ = 12092754582820.

The previous prime is 13302030041101. The next prime is 13302030041119. The reversal of 13302030041113 is 31114003020331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13302030041113 - 2²¹ = 13302027943961 is a prime.

It is a super-3 number, since 3×13302030041113³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13302030041119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604637729131 + ... + 604637729152.

It is an arithmetic number, because the mean of its divisors is an integer number (3627826374852).

Almost surely, 2^{13302030041113} is an apocalyptic number.

It is an amenable number.

13302030041113 is a deficient number, since it is larger than the sum of its proper divisors (1209275458295).

13302030041113 is a wasteful number, since it uses less digits than its factorization.

13302030041113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1209275458294.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13302030041113 its reverse (31114003020331), we get a palindrome (44416033061444).

The spelling of 13302030041113 in words is "thirteen trillion, three hundred two billion, thirty million, forty-one thousand, one hundred thirteen".