Base | Representation |
---|---|
bin | 11110001111101100110110… |
… | …011010011011111010111111 |
3 | 122102222121202120000212200102 |
4 | 132033230312122123322333 |
5 | 114413401131311233231 |
6 | 1150524411453551315 |
7 | 40006255103624102 |
oct | 3617546632337277 |
9 | 572877676025612 |
10 | 133020345024191 |
11 | 3942567aa29789 |
12 | 12b042984a553b |
13 | 592b9c30c3131 |
14 | 24bc30d110739 |
15 | 105a26eeacacb |
hex | 78fb3669bebf |
133020345024191 has 2 divisors, whose sum is σ = 133020345024192. Its totient is φ = 133020345024190.
The previous prime is 133020345024143. The next prime is 133020345024197. The reversal of 133020345024191 is 191420543020331.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (191420543020331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133020345024191 - 230 = 133019271282367 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133020345024197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510172512095 + 66510172512096.
It is an arithmetic number, because the mean of its divisors is an integer number (66510172512096).
Almost surely, 2133020345024191 is an apocalyptic number.
133020345024191 is a deficient number, since it is larger than the sum of its proper divisors (1).
133020345024191 is an equidigital number, since it uses as much as digits as its factorization.
133020345024191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 38.
The spelling of 133020345024191 in words is "one hundred thirty-three trillion, twenty billion, three hundred forty-five million, twenty-four thousand, one hundred ninety-one".
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