Base | Representation |
---|---|
bin | 11110001111101101000001… |
… | …001001110000101111101011 |
3 | 122102222122020010001212201211 |
4 | 132033231001021300233223 |
5 | 114413402013422434121 |
6 | 1150524441411453551 |
7 | 40006262422254040 |
oct | 3617550111605753 |
9 | 572878203055654 |
10 | 133020525202411 |
11 | 39425762703300 |
12 | 12b043288b72b7 |
13 | 592ba2152a172 |
14 | 24bc3290131c7 |
15 | 105a280bedce1 |
hex | 78fb41270beb |
133020525202411 has 48 divisors (see below), whose sum is σ = 174370815650304. Its totient is φ = 99142647120000.
The previous prime is 133020525202391. The next prime is 133020525202423. The reversal of 133020525202411 is 114202525020331.
It is a happy number.
It is not a de Polignac number, because 133020525202411 - 227 = 133020390984683 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133020535202411) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 768458391 + ... + 768631471.
It is an arithmetic number, because the mean of its divisors is an integer number (3632725326048).
Almost surely, 2133020525202411 is an apocalyptic number.
133020525202411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133020525202411 is a deficient number, since it is larger than the sum of its proper divisors (41350290447893).
133020525202411 is a wasteful number, since it uses less digits than its factorization.
133020525202411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 212584 (or 212573 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 133020525202411 in words is "one hundred thirty-three trillion, twenty billion, five hundred twenty-five million, two hundred two thousand, four hundred eleven".
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