Base | Representation |
---|---|
bin | 11110001111101110100000… |
… | …010101011101011000010111 |
3 | 122102222210100101220220100211 |
4 | 132033232200111131120113 |
5 | 114413413301224314333 |
6 | 1150525304054550251 |
7 | 40006350122561563 |
oct | 3617564025353027 |
9 | 572883311826324 |
10 | 133022122104343 |
11 | 3942640205936a |
12 | 12b046b3668387 |
13 | 592bc17319a54 |
14 | 24bc43b13c6a3 |
15 | 105a325ed9ecd |
hex | 78fba055d617 |
133022122104343 has 2 divisors, whose sum is σ = 133022122104344. Its totient is φ = 133022122104342.
The previous prime is 133022122104341. The next prime is 133022122104379. The reversal of 133022122104343 is 343401221220331.
It is a weak prime.
It is an emirp because it is prime and its reverse (343401221220331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133022122104343 - 21 = 133022122104341 is a prime.
Together with 133022122104341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133022122104341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511061052171 + 66511061052172.
It is an arithmetic number, because the mean of its divisors is an integer number (66511061052172).
Almost surely, 2133022122104343 is an apocalyptic number.
133022122104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
133022122104343 is an equidigital number, since it uses as much as digits as its factorization.
133022122104343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 133022122104343 its reverse (343401221220331), we get a palindrome (476423343324674).
The spelling of 133022122104343 in words is "one hundred thirty-three trillion, twenty-two billion, one hundred twenty-two million, one hundred four thousand, three hundred forty-three".
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