Base | Representation |
---|---|
bin | 111101111100011001… |
… | …0100001000011011011 |
3 | 110201100121021010011111 |
4 | 1323320302201003123 |
5 | 4134412342323120 |
6 | 141035424441151 |
7 | 12416301636415 |
oct | 1737062410333 |
9 | 421317233144 |
10 | 133023011035 |
11 | 51462027062 |
12 | 219451791b7 |
13 | c70c284b65 |
14 | 661cb819b5 |
15 | 36d845075a |
hex | 1ef8ca10db |
133023011035 has 8 divisors (see below), whose sum is σ = 159632475120. Its totient is φ = 106415167584.
The previous prime is 133023011029. The next prime is 133023011041. The reversal of 133023011035 is 530110320331.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (133023011029) and next prime (133023011041).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133023011035 - 213 = 133023002843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133023010997 and 133023011015.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 216600 + ... + 559429.
It is an arithmetic number, because the mean of its divisors is an integer number (19954059390).
Almost surely, 2133023011035 is an apocalyptic number.
133023011035 is a deficient number, since it is larger than the sum of its proper divisors (26609464085).
133023011035 is an equidigital number, since it uses as much as digits as its factorization.
133023011035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 810317.
The product of its (nonzero) digits is 810, while the sum is 22.
Adding to 133023011035 its reverse (530110320331), we get a palindrome (663133331366).
The spelling of 133023011035 in words is "one hundred thirty-three billion, twenty-three million, eleven thousand, thirty-five".
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