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133023163354261 is a prime number
BaseRepresentation
bin11110001111101111011110…
…011001100000110010010101
3122102222220000222012212201121
4132033233132121200302111
5114413422414304314021
61150525555252323541
740006414665214615
oct3617573631406225
9572886028185647
10133023163354261
1139426896896894
1212b049443135b1
13592c051c6a66b
1424bc4d9546a45
15105a387618741
hex78fbde660c95

133023163354261 has 2 divisors, whose sum is σ = 133023163354262. Its totient is φ = 133023163354260.

The previous prime is 133023163354259. The next prime is 133023163354273. The reversal of 133023163354261 is 162453361320331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132404375024100 + 618788330161 = 11506710^2 + 786631^2 .

It is a cyclic number.

It is not a de Polignac number, because 133023163354261 - 21 = 133023163354259 is a prime.

It is a super-2 number, since 2×1330231633542612 (a number of 29 digits) contains 22 as substring.

Together with 133023163354259, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133023163354201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511581677130 + 66511581677131.

It is an arithmetic number, because the mean of its divisors is an integer number (66511581677131).

Almost surely, 2133023163354261 is an apocalyptic number.

It is an amenable number.

133023163354261 is a deficient number, since it is larger than the sum of its proper divisors (1).

133023163354261 is an equidigital number, since it uses as much as digits as its factorization.

133023163354261 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 43.

The spelling of 133023163354261 in words is "one hundred thirty-three trillion, twenty-three billion, one hundred sixty-three million, three hundred fifty-four thousand, two hundred sixty-one".