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133023343540126 = 2135116282443851
BaseRepresentation
bin11110001111101111101001…
…001000110111011110011110
3122102222220111112021021021011
4132033233221020313132132
5114413423301421241001
61150530025210325434
740006422313606054
oct3617575110673636
9572886445237234
10133023343540126
1139426979576126
1212b0499472987a
13592c0803a8010
1424bc51544c1d4
15105a39835bd51
hex78fbe923779e

133023343540126 has 8 divisors (see below), whose sum is σ = 214883862641784. Its totient is φ = 61395389326200.

The previous prime is 133023343540103. The next prime is 133023343540147. The reversal of 133023343540126 is 621045343320331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1330233435401262 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2558141221900 + ... + 2558141221951.

It is an arithmetic number, because the mean of its divisors is an integer number (26860482830223).

Almost surely, 2133023343540126 is an apocalyptic number.

133023343540126 is a deficient number, since it is larger than the sum of its proper divisors (81860519101658).

133023343540126 is a wasteful number, since it uses less digits than its factorization.

133023343540126 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5116282443866.

The product of its (nonzero) digits is 466560, while the sum is 40.

Adding to 133023343540126 its reverse (621045343320331), we get a palindrome (754068686860457).

The spelling of 133023343540126 in words is "one hundred thirty-three trillion, twenty-three billion, three hundred forty-three million, five hundred forty thousand, one hundred twenty-six".

Divisors: 1 2 13 26 5116282443851 10232564887702 66511671770063 133023343540126