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133025113443 = 344341704481
BaseRepresentation
bin111101111100011101…
…0100010010101100011
3110201100202012221010110
41323320322202111203
54134413412112233
6141035541502403
712416325544035
oct1737072422543
9421322187113
10133025113443
1151463232692
1221945a11a03
13c70c83caa1
14661d16bc55
1536d8718663
hex1ef8ea2563

133025113443 has 4 divisors (see below), whose sum is σ = 177366817928. Its totient is φ = 88683408960.

The previous prime is 133025113439. The next prime is 133025113471. The reversal of 133025113443 is 344311520331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 133025113443 - 22 = 133025113439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133025113443.

It is not an unprimeable number, because it can be changed into a prime (133025113043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22170852238 + ... + 22170852243.

It is an arithmetic number, because the mean of its divisors is an integer number (44341704482).

Almost surely, 2133025113443 is an apocalyptic number.

133025113443 is a deficient number, since it is larger than the sum of its proper divisors (44341704485).

133025113443 is an equidigital number, since it uses as much as digits as its factorization.

133025113443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44341704484.

The product of its (nonzero) digits is 12960, while the sum is 30.

Adding to 133025113443 its reverse (344311520331), we get a palindrome (477336633774).

The spelling of 133025113443 in words is "one hundred thirty-three billion, twenty-five million, one hundred thirteen thousand, four hundred forty-three".

Divisors: 1 3 44341704481 133025113443