Base | Representation |
---|---|
bin | 11110001111110110110001… |
… | …100100001110100011010110 |
3 | 122110000122021012100210012210 |
4 | 132033312301210032203112 |
5 | 114414034442241414110 |
6 | 1150533333115054250 |
7 | 40010113136153463 |
oct | 3617666144164326 |
9 | 573018235323183 |
10 | 133031001123030 |
11 | 3942a14902853a |
12 | 12b06371141386 |
13 | 592ca009bb56a |
14 | 24bca4046066a |
15 | 105a69576a520 |
hex | 78fdb190e8d6 |
133031001123030 has 32 divisors (see below), whose sum is σ = 319282756639488. Its totient is φ = 35474005416800.
The previous prime is 133031001123019. The next prime is 133031001123037. The reversal of 133031001123030 is 30321100130331.
It is a junction number, because it is equal to n+sod(n) for n = 133031001122988 and 133031001123006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133031001123037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56847456 + ... + 59141315.
It is an arithmetic number, because the mean of its divisors is an integer number (9977586144984).
Almost surely, 2133031001123030 is an apocalyptic number.
133031001123030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133031001123030 is an abundant number, since it is smaller than the sum of its proper divisors (186251755516458).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133031001123030 is a wasteful number, since it uses less digits than its factorization.
133031001123030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116027012.
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 133031001123030 its reverse (30321100130331), we get a palindrome (163352101253361).
The spelling of 133031001123030 in words is "one hundred thirty-three trillion, thirty-one billion, one million, one hundred twenty-three thousand, thirty".
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