Base | Representation |
---|---|
bin | 10011010110111100101… |
… | …011000111000010100110 |
3 | 11201011202121112211210002 |
4 | 103112330223013002212 |
5 | 133243433414441402 |
6 | 2455045222501302 |
7 | 165053221036262 |
oct | 23267453070246 |
9 | 4634677484702 |
10 | 1330310312102 |
11 | 4731aa543302 |
12 | 1959a6294832 |
13 | 985a885ac65 |
14 | 4855cccd0a2 |
15 | 2490ede8602 |
hex | 135bcac70a6 |
1330310312102 has 4 divisors (see below), whose sum is σ = 1995465468156. Its totient is φ = 665155156050.
The previous prime is 1330310312087. The next prime is 1330310312143. The reversal of 1330310312102 is 2012130130331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332577578024 + ... + 332577578027.
It is an arithmetic number, because the mean of its divisors is an integer number (498866367039).
Almost surely, 21330310312102 is an apocalyptic number.
1330310312102 is a deficient number, since it is larger than the sum of its proper divisors (665155156054).
1330310312102 is an equidigital number, since it uses as much as digits as its factorization.
1330310312102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665155156053.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1330310312102 its reverse (2012130130331), we get a palindrome (3342440442433).
The spelling of 1330310312102 in words is "one trillion, three hundred thirty billion, three hundred ten million, three hundred twelve thousand, one hundred two".
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