Base | Representation |
---|---|
bin | 10011010110111100110… |
… | …001111011100010100011 |
3 | 11201011202201220200022122 |
4 | 103112330301323202203 |
5 | 133243434344200003 |
6 | 2455045325054455 |
7 | 165053242163645 |
oct | 23267461734243 |
9 | 4634681820278 |
10 | 1330312100003 |
11 | 473200554607 |
12 | 1959a69b742b |
13 | 985a90359a3 |
14 | 4855d236895 |
15 | 2491014d238 |
hex | 135bcc7b8a3 |
1330312100003 has 4 divisors (see below), whose sum is σ = 1331181018648. Its totient is φ = 1329443181360.
The previous prime is 1330312099979. The next prime is 1330312100053. The reversal of 1330312100003 is 3000012130331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1330312100003 - 214 = 1330312083619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1330312100053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434457026 + ... + 434460087.
It is an arithmetic number, because the mean of its divisors is an integer number (332795254662).
Almost surely, 21330312100003 is an apocalyptic number.
1330312100003 is a deficient number, since it is larger than the sum of its proper divisors (868918645).
1330312100003 is an equidigital number, since it uses as much as digits as its factorization.
1330312100003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 868918644.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 1330312100003 its reverse (3000012130331), we get a palindrome (4330324230334).
The spelling of 1330312100003 in words is "one trillion, three hundred thirty billion, three hundred twelve million, one hundred thousand, three".
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