Base | Representation |
---|---|
bin | 11000110001110110… |
… | …11010100000010011 |
3 | 1021100010012000211101 |
4 | 30120323122200103 |
5 | 204221100131011 |
6 | 10040020125231 |
7 | 650443511644 |
oct | 143073324023 |
9 | 37303160741 |
10 | 13303130131 |
11 | 57072a7625 |
12 | 26b3236817 |
13 | 1340127445 |
14 | 902b156cb |
15 | 52cd7d2c1 |
hex | 318eda813 |
13303130131 has 2 divisors, whose sum is σ = 13303130132. Its totient is φ = 13303130130.
The previous prime is 13303130129. The next prime is 13303130219. The reversal of 13303130131 is 13103130331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13303130131 - 21 = 13303130129 is a prime.
It is a super-2 number, since 2×133031301312 (a number of 21 digits) contains 22 as substring.
Together with 13303130129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13303130099 and 13303130108.
It is not a weakly prime, because it can be changed into another prime (13303136131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651565065 + 6651565066.
It is an arithmetic number, because the mean of its divisors is an integer number (6651565066).
Almost surely, 213303130131 is an apocalyptic number.
13303130131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13303130131 is an equidigital number, since it uses as much as digits as its factorization.
13303130131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 13303130131 its reverse (13103130331), we get a palindrome (26406260462).
The spelling of 13303130131 in words is "thirteen billion, three hundred three million, one hundred thirty thousand, one hundred thirty-one".
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