Base | Representation |
---|---|
bin | 1100000110010110101100… |
… | …1100010011011001011011 |
3 | 1202002210011200201211012012 |
4 | 3001211223030103121123 |
5 | 3220430140344244003 |
6 | 44143242431340135 |
7 | 2542063322055026 |
oct | 301455314233133 |
9 | 52083150654165 |
10 | 13303312103003 |
11 | 42699a2957aaa |
12 | 15aa33038164b |
13 | 75665ca46190 |
14 | 33dc52db41bd |
15 | 1810b29d98d8 |
hex | c196b31365b |
13303312103003 has 4 divisors (see below), whose sum is σ = 14326643803248. Its totient is φ = 12279980402760.
The previous prime is 13303312102967. The next prime is 13303312103021. The reversal of 13303312103003 is 30030121330331.
13303312103003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13303312103003 - 218 = 13303311840859 is a prime.
It is a super-2 number, since 2×133033121030032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13303312103003.
It is not an unprimeable number, because it can be changed into a prime (13303332103003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511665850103 + ... + 511665850128.
It is an arithmetic number, because the mean of its divisors is an integer number (3581660950812).
Almost surely, 213303312103003 is an apocalyptic number.
13303312103003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13303312103003 is a deficient number, since it is larger than the sum of its proper divisors (1023331700245).
13303312103003 is a wasteful number, since it uses less digits than its factorization.
13303312103003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1023331700244.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13303312103003 its reverse (30030121330331), we get a palindrome (43333433433334).
The spelling of 13303312103003 in words is "thirteen trillion, three hundred three billion, three hundred twelve million, one hundred three thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •