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1330409501 is a prime number
BaseRepresentation
bin100111101001100…
…0111000000011101
310102201101210201222
41033103013000131
510211041101001
6340003143125
744653202621
oct11723070035
93381353658
101330409501
11622a88393
12311674aa5
13182824475
14c8999181
157bbea61b
hex4f4c701d

1330409501 has 2 divisors, whose sum is σ = 1330409502. Its totient is φ = 1330409500.

The previous prime is 1330409473. The next prime is 1330409503. The reversal of 1330409501 is 1059040331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1309716100 + 20693401 = 36190^2 + 4549^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330409501 - 226 = 1263300637 is a prime.

Together with 1330409503, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330409503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665204750 + 665204751.

It is an arithmetic number, because the mean of its divisors is an integer number (665204751).

Almost surely, 21330409501 is an apocalyptic number.

It is an amenable number.

1330409501 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330409501 is an equidigital number, since it uses as much as digits as its factorization.

1330409501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 26.

The square root of 1330409501 is about 36474.7789712289. The cubic root of 1330409501 is about 1099.8373040367.

Adding to 1330409501 its reverse (1059040331), we get a palindrome (2389449832).

The spelling of 1330409501 in words is "one billion, three hundred thirty million, four hundred nine thousand, five hundred one".