Base | Representation |
---|---|
bin | 10011010111000010101… |
… | …000001101010001100101 |
3 | 11201012000120112102002221 |
4 | 103113002220031101211 |
5 | 133244140003331001 |
6 | 2455103152032341 |
7 | 165055543144024 |
oct | 23270250152145 |
9 | 4635016472087 |
10 | 1330410214501 |
11 | 473250978475 |
12 | 195a138326b1 |
13 | 985c34691c4 |
14 | 4856c2968bb |
15 | 24918a7e1a1 |
hex | 135c2a0d465 |
1330410214501 has 2 divisors, whose sum is σ = 1330410214502. Its totient is φ = 1330410214500.
The previous prime is 1330410214499. The next prime is 1330410214513. The reversal of 1330410214501 is 1054120140331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 779362324225 + 551047890276 = 882815^2 + 742326^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330410214501 - 21 = 1330410214499 is a prime.
Together with 1330410214499, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330410214531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665205107250 + 665205107251.
It is an arithmetic number, because the mean of its divisors is an integer number (665205107251).
Almost surely, 21330410214501 is an apocalyptic number.
It is an amenable number.
1330410214501 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330410214501 is an equidigital number, since it uses as much as digits as its factorization.
1330410214501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1330410214501 its reverse (1054120140331), we get a palindrome (2384530354832).
The spelling of 1330410214501 in words is "one trillion, three hundred thirty billion, four hundred ten million, two hundred fourteen thousand, five hundred one".
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