Base | Representation |
---|---|
bin | 10011010111000010110… |
… | …110110001101001100111 |
3 | 11201012000211201102210202 |
4 | 103113002312301221213 |
5 | 133244141443033021 |
6 | 2455103405541115 |
7 | 165055620461123 |
oct | 23270266615147 |
9 | 4635024642722 |
10 | 1330414033511 |
11 | 473253046782 |
12 | 195a14b7479b |
13 | 985c41a5584 |
14 | 4856c9ac583 |
15 | 24919085a0b |
hex | 135c2db1a67 |
1330414033511 has 2 divisors, whose sum is σ = 1330414033512. Its totient is φ = 1330414033510.
The previous prime is 1330414033489. The next prime is 1330414033577. The reversal of 1330414033511 is 1153304140331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330414033511 - 222 = 1330409839207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330414033211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665207016755 + 665207016756.
It is an arithmetic number, because the mean of its divisors is an integer number (665207016756).
Almost surely, 21330414033511 is an apocalyptic number.
1330414033511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330414033511 is an equidigital number, since it uses as much as digits as its factorization.
1330414033511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1330414033511 its reverse (1153304140331), we get a palindrome (2483718173842).
The spelling of 1330414033511 in words is "one trillion, three hundred thirty billion, four hundred fourteen million, thirty-three thousand, five hundred eleven".
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