Base | Representation |
---|---|
bin | 1100000110011010001000… |
… | …0001011100011100000110 |
3 | 1202002212112210200121012211 |
4 | 3001212202001130130012 |
5 | 3220434031343101314 |
6 | 44143514012134034 |
7 | 2542125162066136 |
oct | 301464201343406 |
9 | 52085483617184 |
10 | 13304232003334 |
11 | 426a325141808 |
12 | 15aa54846731a |
13 | 7567784b97bc |
14 | 33dcdd230ac6 |
15 | 1811186479c4 |
hex | c19a205c706 |
13304232003334 has 4 divisors (see below), whose sum is σ = 19956348005004. Its totient is φ = 6652116001666.
The previous prime is 13304232003317. The next prime is 13304232003343. The reversal of 13304232003334 is 43330023240331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13304232003296 and 13304232003305.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3326058000832 + ... + 3326058000835.
It is an arithmetic number, because the mean of its divisors is an integer number (4989087001251).
Almost surely, 213304232003334 is an apocalyptic number.
13304232003334 is a deficient number, since it is larger than the sum of its proper divisors (6652116001670).
13304232003334 is an equidigital number, since it uses as much as digits as its factorization.
13304232003334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6652116001669.
The product of its (nonzero) digits is 46656, while the sum is 31.
Adding to 13304232003334 its reverse (43330023240331), we get a palindrome (56634255243665).
The spelling of 13304232003334 in words is "thirteen trillion, three hundred four billion, two hundred thirty-two million, three thousand, three hundred thirty-four".
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