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13304232003334 = 26652116001667
BaseRepresentation
bin1100000110011010001000…
…0001011100011100000110
31202002212112210200121012211
43001212202001130130012
53220434031343101314
644143514012134034
72542125162066136
oct301464201343406
952085483617184
1013304232003334
11426a325141808
1215aa54846731a
137567784b97bc
1433dcdd230ac6
151811186479c4
hexc19a205c706

13304232003334 has 4 divisors (see below), whose sum is σ = 19956348005004. Its totient is φ = 6652116001666.

The previous prime is 13304232003317. The next prime is 13304232003343. The reversal of 13304232003334 is 43330023240331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13304232003296 and 13304232003305.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3326058000832 + ... + 3326058000835.

It is an arithmetic number, because the mean of its divisors is an integer number (4989087001251).

Almost surely, 213304232003334 is an apocalyptic number.

13304232003334 is a deficient number, since it is larger than the sum of its proper divisors (6652116001670).

13304232003334 is an equidigital number, since it uses as much as digits as its factorization.

13304232003334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6652116001669.

The product of its (nonzero) digits is 46656, while the sum is 31.

Adding to 13304232003334 its reverse (43330023240331), we get a palindrome (56634255243665).

The spelling of 13304232003334 in words is "thirteen trillion, three hundred four billion, two hundred thirty-two million, three thousand, three hundred thirty-four".

Divisors: 1 2 6652116001667 13304232003334