133043220114103 has 4 divisors (see below), whose sum is σ = 143277313969048. Its totient is φ = 122809126259160.

The previous prime is 133043220114083. The next prime is 133043220114107. The reversal of 133043220114103 is 301411022340331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133043220114103 - 2³³ = 133034630179511 is a prime.

It is a super-2 number, since 2×133043220114103² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133043220114107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5117046927453 + ... + 5117046927478.

It is an arithmetic number, because the mean of its divisors is an integer number (35819328492262).

Almost surely, 2^{133043220114103} is an apocalyptic number.

133043220114103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

133043220114103 is a deficient number, since it is larger than the sum of its proper divisors (10234093854945).

133043220114103 is a wasteful number, since it uses less digits than its factorization.

133043220114103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10234093854944.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 133043220114103 its reverse (301411022340331), we get a palindrome (434454242454434).

The spelling of 133043220114103 in words is "one hundred thirty-three trillion, forty-three billion, two hundred twenty million, one hundred fourteen thousand, one hundred three".