Base | Representation |
---|---|
bin | 111101111100111111… |
… | …1111111111010101101 |
3 | 110201102000111001022111 |
4 | 1323321333333322231 |
5 | 4134433042310131 |
6 | 141041432044021 |
7 | 12416636403553 |
oct | 1737177777255 |
9 | 421360431274 |
10 | 133043322541 |
11 | 5147253a428 |
12 | 2194bb33611 |
13 | c713546cbc |
14 | 662174bbd3 |
15 | 36da113ab1 |
hex | 1ef9fffead |
133043322541 has 2 divisors, whose sum is σ = 133043322542. Its totient is φ = 133043322540.
The previous prime is 133043322499. The next prime is 133043322553. The reversal of 133043322541 is 145223340331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79507080900 + 53536241641 = 281970^2 + 231379^2 .
It is a cyclic number.
It is not a de Polignac number, because 133043322541 - 221 = 133041225389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133043320541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66521661270 + 66521661271.
It is an arithmetic number, because the mean of its divisors is an integer number (66521661271).
Almost surely, 2133043322541 is an apocalyptic number.
It is an amenable number.
133043322541 is a deficient number, since it is larger than the sum of its proper divisors (1).
133043322541 is an equidigital number, since it uses as much as digits as its factorization.
133043322541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 133043322541 its reverse (145223340331), we get a palindrome (278266662872).
The spelling of 133043322541 in words is "one hundred thirty-three billion, forty-three million, three hundred twenty-two thousand, five hundred forty-one".
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