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133044000000 = 2835611087
BaseRepresentation
bin111101111101000001…
…0100101010100000000
3110201102001202110121120
41323322002211110000
54134433231000000
6141041454352240
712416645224632
oct1737202452400
9421361673546
10133044000000
115147296240a
12219501bb680
13c713723472
146621886a52
1536da1e96a0
hex1efa0a5500

133044000000 has 252 divisors, whose sum is σ = 442648084032. Its totient is φ = 35475200000.

The previous prime is 133043999989. The next prime is 133044000071. The reversal of 133044000000 is 440331.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 11994457 + ... + 12005543.

It is an arithmetic number, because the mean of its divisors is an integer number (1756540016).

Almost surely, 2133044000000 is an apocalyptic number.

133044000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133044000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221324042016).

133044000000 is an abundant number, since it is smaller than the sum of its proper divisors (309604084032).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133044000000 is an frugal number, since it uses more digits than its factorization.

133044000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11136 (or 11097 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 133044000000 its reverse (440331), we get a palindrome (133044440331).

The spelling of 133044000000 in words is "one hundred thirty-three billion, forty-four million", and thus it is an aban number.