Base | Representation |
---|---|
bin | 111101111101000001… |
… | …0100101010101000111 |
3 | 110201102001202110201012 |
4 | 1323322002211111013 |
5 | 4134433231000241 |
6 | 141041454352435 |
7 | 12416645225063 |
oct | 1737202452507 |
9 | 421361673635 |
10 | 133044000071 |
11 | 51472962474 |
12 | 219501bb71b |
13 | c7137234c8 |
14 | 6621886aa3 |
15 | 36da1e96eb |
hex | 1efa0a5547 |
133044000071 has 2 divisors, whose sum is σ = 133044000072. Its totient is φ = 133044000070.
The previous prime is 133043999989. The next prime is 133044000073. The reversal of 133044000071 is 170000440331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133044000071 - 230 = 131970258247 is a prime.
Together with 133044000073, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133044000073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66522000035 + 66522000036.
It is an arithmetic number, because the mean of its divisors is an integer number (66522000036).
Almost surely, 2133044000071 is an apocalyptic number.
133044000071 is a deficient number, since it is larger than the sum of its proper divisors (1).
133044000071 is an equidigital number, since it uses as much as digits as its factorization.
133044000071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 23.
The spelling of 133044000071 in words is "one hundred thirty-three billion, forty-four million, seventy-one", and thus it is an aban number.
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