Base | Representation |
---|---|
bin | 111101111101000001… |
… | …1100110000010110101 |
3 | 110201102002020221022121 |
4 | 1323322003212002311 |
5 | 4134433312441031 |
6 | 141041504155541 |
7 | 12416650410634 |
oct | 1737203460265 |
9 | 421362227277 |
10 | 133044265141 |
11 | 51473023637 |
12 | 21950308bb1 |
13 | c7137b7058 |
14 | 662191551b |
15 | 36da24d011 |
hex | 1efa0e60b5 |
133044265141 has 4 divisors (see below), whose sum is σ = 138828798432. Its totient is φ = 127259731852.
The previous prime is 133044265139. The next prime is 133044265163. The reversal of 133044265141 is 141562440331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133044265141 - 21 = 133044265139 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133044265097 and 133044265106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133044265121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2892266611 + ... + 2892266656.
It is an arithmetic number, because the mean of its divisors is an integer number (34707199608).
Almost surely, 2133044265141 is an apocalyptic number.
It is an amenable number.
133044265141 is a deficient number, since it is larger than the sum of its proper divisors (5784533291).
133044265141 is an equidigital number, since it uses as much as digits as its factorization.
133044265141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5784533290.
The product of its (nonzero) digits is 34560, while the sum is 34.
The spelling of 133044265141 in words is "one hundred thirty-three billion, forty-four million, two hundred sixty-five thousand, one hundred forty-one".
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