Base | Representation |
---|---|
bin | 111101111101000011… |
… | …0110010111100010101 |
3 | 110201102010211120120110 |
4 | 1323322012302330111 |
5 | 4134434021320110 |
6 | 141041534153233 |
7 | 12416660504523 |
oct | 1737206627425 |
9 | 421363746513 |
10 | 133045104405 |
11 | 51473547144 |
12 | 21950652819 |
13 | c713a1c065 |
14 | 6621a93313 |
15 | 36da366a20 |
hex | 1efa1b2f15 |
133045104405 has 16 divisors (see below), whose sum is σ = 212878958400. Its totient is φ = 70955125248.
The previous prime is 133045104397. The next prime is 133045104407. The reversal of 133045104405 is 504401540331.
It is not a de Polignac number, because 133045104405 - 23 = 133045104397 is a prime.
It is a super-2 number, since 2×1330451044052 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133045104407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 414949 + ... + 662021.
It is an arithmetic number, because the mean of its divisors is an integer number (13304934900).
Almost surely, 2133045104405 is an apocalyptic number.
133045104405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
133045104405 is a deficient number, since it is larger than the sum of its proper divisors (79833853995).
133045104405 is a wasteful number, since it uses less digits than its factorization.
133045104405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 282980.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 133045104405 its reverse (504401540331), we get a palindrome (637446644736).
The spelling of 133045104405 in words is "one hundred thirty-three billion, forty-five million, one hundred four thousand, four hundred five".
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