Base | Representation |
---|---|
bin | 10011010111001000101… |
… | …101101011100001110111 |
3 | 11201012021200122112011001 |
4 | 103113020231223201313 |
5 | 133244342122444224 |
6 | 2455121240224131 |
7 | 165061223024452 |
oct | 23271055534167 |
9 | 4635250575131 |
10 | 1330512312439 |
11 | 4732a3572132 |
12 | 195a41a6b047 |
13 | 9860b66589b |
14 | 4857ba72499 |
15 | 249229ea544 |
hex | 135c8b6b877 |
1330512312439 has 2 divisors, whose sum is σ = 1330512312440. Its totient is φ = 1330512312438.
The previous prime is 1330512312401. The next prime is 1330512312509. The reversal of 1330512312439 is 9342132150331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330512312439 - 217 = 1330512181367 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1330512312398 and 1330512312407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330512312139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665256156219 + 665256156220.
It is an arithmetic number, because the mean of its divisors is an integer number (665256156220).
Almost surely, 21330512312439 is an apocalyptic number.
1330512312439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330512312439 is an equidigital number, since it uses as much as digits as its factorization.
1330512312439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 1330512312439 in words is "one trillion, three hundred thirty billion, five hundred twelve million, three hundred twelve thousand, four hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •