Base | Representation |
---|---|
bin | 1100000110011101011110… |
… | …1100010110011011000111 |
3 | 1202002221212120000200200111 |
4 | 3001213113230112123013 |
5 | 3220442402401141320 |
6 | 44144143215453451 |
7 | 2542156404516505 |
oct | 301472754263307 |
9 | 52087776020614 |
10 | 13305132443335 |
11 | 426a7474446a7 |
12 | 15aa759b27287 |
13 | 75688cc08535 |
14 | 33dd86a63675 |
15 | 18116c70ea5a |
hex | c19d7b166c7 |
13305132443335 has 8 divisors (see below), whose sum is σ = 15978374822736. Its totient is φ = 10635962027520.
The previous prime is 13305132443329. The next prime is 13305132443401. The reversal of 13305132443335 is 53334423150331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13305132443335 - 213 = 13305132435143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1017983706 + ... + 1017996775.
It is an arithmetic number, because the mean of its divisors is an integer number (1997296852842).
Almost surely, 213305132443335 is an apocalyptic number.
13305132443335 is a deficient number, since it is larger than the sum of its proper divisors (2673242379401).
13305132443335 is a wasteful number, since it uses less digits than its factorization.
13305132443335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2035981793.
The product of its (nonzero) digits is 583200, while the sum is 40.
Adding to 13305132443335 its reverse (53334423150331), we get a palindrome (66639555593666).
The spelling of 13305132443335 in words is "thirteen trillion, three hundred five billion, one hundred thirty-two million, four hundred forty-three thousand, three hundred thirty-five".
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