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13305132443335 = 513072035980481
BaseRepresentation
bin1100000110011101011110…
…1100010110011011000111
31202002221212120000200200111
43001213113230112123013
53220442402401141320
644144143215453451
72542156404516505
oct301472754263307
952087776020614
1013305132443335
11426a7474446a7
1215aa759b27287
1375688cc08535
1433dd86a63675
1518116c70ea5a
hexc19d7b166c7

13305132443335 has 8 divisors (see below), whose sum is σ = 15978374822736. Its totient is φ = 10635962027520.

The previous prime is 13305132443329. The next prime is 13305132443401. The reversal of 13305132443335 is 53334423150331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13305132443335 - 213 = 13305132435143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1017983706 + ... + 1017996775.

It is an arithmetic number, because the mean of its divisors is an integer number (1997296852842).

Almost surely, 213305132443335 is an apocalyptic number.

13305132443335 is a deficient number, since it is larger than the sum of its proper divisors (2673242379401).

13305132443335 is a wasteful number, since it uses less digits than its factorization.

13305132443335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2035981793.

The product of its (nonzero) digits is 583200, while the sum is 40.

Adding to 13305132443335 its reverse (53334423150331), we get a palindrome (66639555593666).

The spelling of 13305132443335 in words is "thirteen trillion, three hundred five billion, one hundred thirty-two million, four hundred forty-three thousand, three hundred thirty-five".

Divisors: 1 5 1307 6535 2035980481 10179902405 2661026488667 13305132443335