Base | Representation |
---|---|
bin | 1100000110011110001011… |
… | …1001110111000000100111 |
3 | 1202002222100122221200122110 |
4 | 3001213202321313000213 |
5 | 3220443244024042210 |
6 | 44144214015132103 |
7 | 2542164150333114 |
oct | 301474271670047 |
9 | 52088318850573 |
10 | 13305320534055 |
11 | 426a833632a80 |
12 | 15aa7b0b14033 |
13 | 7568bcb82c14 |
14 | 33dda3a2590b |
15 | 18117deb5420 |
hex | c19e2e77027 |
13305320534055 has 32 divisors (see below), whose sum is σ = 23604550783488. Its totient is φ = 6345309340800.
The previous prime is 13305320534047. The next prime is 13305320534117. The reversal of 13305320534055 is 55043502350331.
13305320534055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13305320534055 - 23 = 13305320534047 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 660959659 + ... + 660979788.
It is an arithmetic number, because the mean of its divisors is an integer number (737642211984).
Almost surely, 213305320534055 is an apocalyptic number.
13305320534055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13305320534055 is a deficient number, since it is larger than the sum of its proper divisors (10299230249433).
13305320534055 is a wasteful number, since it uses less digits than its factorization.
13305320534055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1321939527.
The product of its (nonzero) digits is 405000, while the sum is 39.
Adding to 13305320534055 its reverse (55043502350331), we get a palindrome (68348822884386).
The spelling of 13305320534055 in words is "thirteen trillion, three hundred five billion, three hundred twenty million, five hundred thirty-four thousand, fifty-five".
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