Search a number
-
+
133054554312103 is a prime number
BaseRepresentation
bin11110010000001100101101…
…011100100000110110100111
3122110002220001122211202112211
4132100030231130200312213
5114414431211400441403
61150552230213424251
740011605615026264
oct3620145534406647
9573086048752484
10133054554312103
1139439135203056
1212b0aa4503b087
135931cb5566628
1424bdc365cc26b
15105b0c33ed06d
hex79032d720da7

133054554312103 has 2 divisors, whose sum is σ = 133054554312104. Its totient is φ = 133054554312102.

The previous prime is 133054554312091. The next prime is 133054554312139. The reversal of 133054554312103 is 301213455450331.

It is a weak prime.

It is an emirp because it is prime and its reverse (301213455450331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133054554312103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133054554312143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66527277156051 + 66527277156052.

It is an arithmetic number, because the mean of its divisors is an integer number (66527277156052).

Almost surely, 2133054554312103 is an apocalyptic number.

133054554312103 is a deficient number, since it is larger than the sum of its proper divisors (1).

133054554312103 is an equidigital number, since it uses as much as digits as its factorization.

133054554312103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 133054554312103 in words is "one hundred thirty-three trillion, fifty-four billion, five hundred fifty-four million, three hundred twelve thousand, one hundred three".