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133064650243247 is a prime number
BaseRepresentation
bin11110010000010110000111…
…001101011011110010101111
3122110010212010021010012110112
4132100112013031123302233
5114420112400430240442
61151001020104330235
740012414036026002
oct3620260715336257
9573125107105415
10133064650243247
113944244608a5a8
1212b109a217397b
135932c340a1598
1424c05133a3539
15105b4b490a082
hex79058735bcaf

133064650243247 has 2 divisors, whose sum is σ = 133064650243248. Its totient is φ = 133064650243246.

The previous prime is 133064650243229. The next prime is 133064650243313. The reversal of 133064650243247 is 742342056460331.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (742342056460331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133064650243247 - 212 = 133064650239151 is a prime.

It is a super-2 number, since 2×1330646502432472 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133064650243195 and 133064650243204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133064650243747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66532325121623 + 66532325121624.

It is an arithmetic number, because the mean of its divisors is an integer number (66532325121624).

Almost surely, 2133064650243247 is an apocalyptic number.

133064650243247 is a deficient number, since it is larger than the sum of its proper divisors (1).

133064650243247 is an equidigital number, since it uses as much as digits as its factorization.

133064650243247 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8709120, while the sum is 50.

The spelling of 133064650243247 in words is "one hundred thirty-three trillion, sixty-four billion, six hundred fifty million, two hundred forty-three thousand, two hundred forty-seven".