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133069841509961 is a prime number
BaseRepresentation
bin11110010000011010111100…
…101000100010111001001001
3122110011100112001101212122002
4132100122330220202321021
5114420204013411304321
61151003235151240345
740012656503045246
oct3620327450427111
9573140461355562
10133069841509961
113944466a455074
1212b119b08190b5
13593358074a335
1424c0886a125cd
15105b6ba54320b
hex7906bca22e49

133069841509961 has 2 divisors, whose sum is σ = 133069841509962. Its totient is φ = 133069841509960.

The previous prime is 133069841509823. The next prime is 133069841509963. The reversal of 133069841509961 is 169905148960331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70171364617225 + 62898476892736 = 8376835^2 + 7930856^2 .

It is a cyclic number.

It is not a de Polignac number, because 133069841509961 - 234 = 133052661640777 is a prime.

It is a super-2 number, since 2×1330698415099612 (a number of 29 digits) contains 22 as substring.

Together with 133069841509963, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133069841509963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66534920754980 + 66534920754981.

It is an arithmetic number, because the mean of its divisors is an integer number (66534920754981).

Almost surely, 2133069841509961 is an apocalyptic number.

It is an amenable number.

133069841509961 is a deficient number, since it is larger than the sum of its proper divisors (1).

133069841509961 is an equidigital number, since it uses as much as digits as its factorization.

133069841509961 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37791360, while the sum is 65.

The spelling of 133069841509961 in words is "one hundred thirty-three trillion, sixty-nine billion, eight hundred forty-one million, five hundred nine thousand, nine hundred sixty-one".