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133069841509963 is a prime number
BaseRepresentation
bin11110010000011010111100…
…101000100010111001001011
3122110011100112001101212122011
4132100122330220202321023
5114420204013411304323
61151003235151240351
740012656503045251
oct3620327450427113
9573140461355564
10133069841509963
113944466a455076
1212b119b08190b7
13593358074a337
1424c0886a125d1
15105b6ba54320d
hex7906bca22e4b

133069841509963 has 2 divisors, whose sum is σ = 133069841509964. Its totient is φ = 133069841509962.

The previous prime is 133069841509961. The next prime is 133069841509973. The reversal of 133069841509963 is 369905148960331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133069841509963 - 21 = 133069841509961 is a prime.

It is a super-2 number, since 2×1330698415099632 (a number of 29 digits) contains 22 as substring.

Together with 133069841509961, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133069841509961) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66534920754981 + 66534920754982.

It is an arithmetic number, because the mean of its divisors is an integer number (66534920754982).

Almost surely, 2133069841509963 is an apocalyptic number.

133069841509963 is a deficient number, since it is larger than the sum of its proper divisors (1).

133069841509963 is an equidigital number, since it uses as much as digits as its factorization.

133069841509963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113374080, while the sum is 67.

The spelling of 133069841509963 in words is "one hundred thirty-three trillion, sixty-nine billion, eight hundred forty-one million, five hundred nine thousand, nine hundred sixty-three".