Base | Representation |
---|---|
bin | 11110010000011010111100… |
… | …101000100010111001001011 |
3 | 122110011100112001101212122011 |
4 | 132100122330220202321023 |
5 | 114420204013411304323 |
6 | 1151003235151240351 |
7 | 40012656503045251 |
oct | 3620327450427113 |
9 | 573140461355564 |
10 | 133069841509963 |
11 | 3944466a455076 |
12 | 12b119b08190b7 |
13 | 593358074a337 |
14 | 24c0886a125d1 |
15 | 105b6ba54320d |
hex | 7906bca22e4b |
133069841509963 has 2 divisors, whose sum is σ = 133069841509964. Its totient is φ = 133069841509962.
The previous prime is 133069841509961. The next prime is 133069841509973. The reversal of 133069841509963 is 369905148960331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133069841509963 - 21 = 133069841509961 is a prime.
It is a super-2 number, since 2×1330698415099632 (a number of 29 digits) contains 22 as substring.
Together with 133069841509961, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (133069841509961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66534920754981 + 66534920754982.
It is an arithmetic number, because the mean of its divisors is an integer number (66534920754982).
Almost surely, 2133069841509963 is an apocalyptic number.
133069841509963 is a deficient number, since it is larger than the sum of its proper divisors (1).
133069841509963 is an equidigital number, since it uses as much as digits as its factorization.
133069841509963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 113374080, while the sum is 67.
The spelling of 133069841509963 in words is "one hundred thirty-three trillion, sixty-nine billion, eight hundred forty-one million, five hundred nine thousand, nine hundred sixty-three".
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