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1330802706047 is a prime number
BaseRepresentation
bin10011010111011010000…
…001011100011001111111
311201020000221002001021212
4103113122001130121333
5133300440443043142
62455210132315035
7165101350234163
oct23273201343177
94636027061255
101330802706047
11473432485151
12195b03172a7b
139865687c019
14485a8464ca3
152493d25cd82
hex135da05c67f

1330802706047 has 2 divisors, whose sum is σ = 1330802706048. Its totient is φ = 1330802706046.

The previous prime is 1330802706017. The next prime is 1330802706127. The reversal of 1330802706047 is 7406072080331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1330802706047 - 212 = 1330802701951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330802705995 and 1330802706013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330802706017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665401353023 + 665401353024.

It is an arithmetic number, because the mean of its divisors is an integer number (665401353024).

Almost surely, 21330802706047 is an apocalyptic number.

1330802706047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330802706047 is an equidigital number, since it uses as much as digits as its factorization.

1330802706047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 169344, while the sum is 41.

Adding to 1330802706047 its reverse (7406072080331), we get a palindrome (8736874786378).

The spelling of 1330802706047 in words is "one trillion, three hundred thirty billion, eight hundred two million, seven hundred six thousand, forty-seven".