Base | Representation |
---|---|
bin | 10011010111100101110… |
… | …010100011100111010001 |
3 | 11201020112200120020001011 |
4 | 103113211302203213101 |
5 | 133301342013130001 |
6 | 2455241504010521 |
7 | 165106265302213 |
oct | 23274562434721 |
9 | 4636480506034 |
10 | 1331000130001 |
11 | 473523968743 |
12 | 195b59300a41 |
13 | 98688743929 |
14 | 485c67765b3 |
15 | 24950758d51 |
hex | 135e5ca39d1 |
1331000130001 has 2 divisors, whose sum is σ = 1331000130002. Its totient is φ = 1331000130000.
The previous prime is 1331000129993. The next prime is 1331000130011. The reversal of 1331000130001 is 1000310001331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1174915084225 + 156085045776 = 1083935^2 + 395076^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331000130001 - 23 = 1331000129993 is a prime.
It is a super-2 number, since 2×13310001300012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1331000130011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665500065000 + 665500065001.
It is an arithmetic number, because the mean of its divisors is an integer number (665500065001).
Almost surely, 21331000130001 is an apocalyptic number.
It is an amenable number.
1331000130001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331000130001 is an equidigital number, since it uses as much as digits as its factorization.
1331000130001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 13.
Adding to 1331000130001 its reverse (1000310001331), we get a palindrome (2331310131332).
The spelling of 1331000130001 in words is "one trillion, three hundred thirty-one billion, one hundred thirty thousand, one".
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