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13310003002 = 26655001501
BaseRepresentation
bin11000110010101011…
…01000011100111010
31021100121010012122011
430121111220130322
5204224330044002
610040423320134
7650556105322
oct143125503472
937317105564
1013310003002
11571017128a
1226b55b004a
13134169282a
149039c4282
1552d7898d7
hex31956873a

13310003002 has 4 divisors (see below), whose sum is σ = 19965004506. Its totient is φ = 6655001500.

The previous prime is 13310002997. The next prime is 13310003011. The reversal of 13310003002 is 20030001331.

13310003002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20030001331 = 139144100729.

It can be written as a sum of positive squares in only one way, i.e., 8966006721 + 4343996281 = 94689^2 + 65909^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327500749 + ... + 3327500752.

Almost surely, 213310003002 is an apocalyptic number.

13310003002 is a deficient number, since it is larger than the sum of its proper divisors (6655001504).

13310003002 is an equidigital number, since it uses as much as digits as its factorization.

13310003002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655001503.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 13310003002 its reverse (20030001331), we get a palindrome (33340004333).

The spelling of 13310003002 in words is "thirteen billion, three hundred ten million, three thousand, two".

Divisors: 1 2 6655001501 13310003002