133100100020021 has 2 divisors, whose sum is σ = 133100100020022. Its totient is φ = 133100100020020.

The previous prime is 133100100019987. The next prime is 133100100020023. The reversal of 133100100020021 is 120020001001331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115432461602500 + 17667638417521 = 10743950^2 + 4203289^2 .

It is an emirp because it is prime and its reverse (120020001001331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133100100020021 is a prime.

Together with 133100100020023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133100100019978 and 133100100020005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133100100020023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550050010010 + 66550050010011.

It is an arithmetic number, because the mean of its divisors is an integer number (66550050010011).

Almost surely, 2^{133100100020021} is an apocalyptic number.

It is an amenable number.

133100100020021 is a deficient number, since it is larger than the sum of its proper divisors (1).

133100100020021 is an equidigital number, since it uses as much as digits as its factorization.

133100100020021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 133100100020021 its reverse (120020001001331), we get a palindrome (253120101021352).

The spelling of 133100100020021 in words is "one hundred thirty-three trillion, one hundred billion, one hundred million, twenty thousand, twenty-one".