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133100112022 = 266550056011
BaseRepresentation
bin111101111110101100…
…0101000100010010110
3110201112222100020211121
41323331120220202112
54140042112041042
6141051221154154
712421226166553
oct1737530504226
9421488306747
10133100112022
11514a15a8189
1221966b5b95a
13c72223b847
1466290d1a2a
1536e00d0367
hex1efd628896

133100112022 has 4 divisors (see below), whose sum is σ = 199650168036. Its totient is φ = 66550056010.

The previous prime is 133100111983. The next prime is 133100112043. The reversal of 133100112022 is 220211001331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 133100111987 and 133100112005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33275028004 + ... + 33275028007.

It is an arithmetic number, because the mean of its divisors is an integer number (49912542009).

Almost surely, 2133100112022 is an apocalyptic number.

133100112022 is a deficient number, since it is larger than the sum of its proper divisors (66550056014).

133100112022 is an equidigital number, since it uses as much as digits as its factorization.

133100112022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66550056013.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 133100112022 its reverse (220211001331), we get a palindrome (353311113353).

The spelling of 133100112022 in words is "one hundred thirty-three billion, one hundred million, one hundred twelve thousand, twenty-two".

Divisors: 1 2 66550056011 133100112022