1331003201101 has 4 divisors (see below), whose sum is σ = 1521146515552. Its totient is φ = 1140859886652.

The previous prime is 1331003201053. The next prime is 1331003201221. The reversal of 1331003201101 is 1011023001331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331003201101 - 2⁷ = 1331003200973 is a prime.

It is a super-2 number, since 2×1331003201101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331003201401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95071657215 + ... + 95071657228.

It is an arithmetic number, because the mean of its divisors is an integer number (380286628888).

Almost surely, 2^{1331003201101} is an apocalyptic number.

It is an amenable number.

1331003201101 is a deficient number, since it is larger than the sum of its proper divisors (190143314451).

1331003201101 is an equidigital number, since it uses as much as digits as its factorization.

1331003201101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190143314450.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1331003201101 its reverse (1011023001331), we get a palindrome (2342026202432).

The spelling of 1331003201101 in words is "one trillion, three hundred thirty-one billion, three million, two hundred one thousand, one hundred one".