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13310120100103 is a prime number
BaseRepresentation
bin1100000110110000000011…
…1110110000000100000111
31202010102202011011220111221
43001230000332300010013
53221033111221200403
644150330150341211
72542424120065051
oct301540076600407
952112664156457
1013310120100103
114271876890a92
1215ab71035a807
137571a6334b28
143402db2308d1
15181360528dbd
hexc1b00fb0107

13310120100103 has 2 divisors, whose sum is σ = 13310120100104. Its totient is φ = 13310120100102.

The previous prime is 13310120100037. The next prime is 13310120100139. The reversal of 13310120100103 is 30100102101331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13310120100103 is a prime.

It is a super-2 number, since 2×133101201001032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13310120100203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655060050051 + 6655060050052.

It is an arithmetic number, because the mean of its divisors is an integer number (6655060050052).

Almost surely, 213310120100103 is an apocalyptic number.

13310120100103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13310120100103 is an equidigital number, since it uses as much as digits as its factorization.

13310120100103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13310120100103 its reverse (30100102101331), we get a palindrome (43410222201434).

The spelling of 13310120100103 in words is "thirteen trillion, three hundred ten billion, one hundred twenty million, one hundred thousand, one hundred three".