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133101211223 is a prime number
BaseRepresentation
bin111101111110101110…
…0110100111001010111
3110201120001102002122202
41323331130310321113
54140042402224343
6141051300515115
712421241425331
oct1737534647127
9421501362582
10133101211223
11514a2189012
12219673aba9b
13c722534c66
1466292da451
1536e024adb8
hex1efd734e57

133101211223 has 2 divisors, whose sum is σ = 133101211224. Its totient is φ = 133101211222.

The previous prime is 133101211219. The next prime is 133101211241. The reversal of 133101211223 is 322112101331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133101211223 - 22 = 133101211219 is a prime.

It is a super-2 number, since 2×1331012112232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133101211195 and 133101211204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133101211213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66550605611 + 66550605612.

It is an arithmetic number, because the mean of its divisors is an integer number (66550605612).

Almost surely, 2133101211223 is an apocalyptic number.

133101211223 is a deficient number, since it is larger than the sum of its proper divisors (1).

133101211223 is an equidigital number, since it uses as much as digits as its factorization.

133101211223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 133101211223 its reverse (322112101331), we get a palindrome (455213312554).

The spelling of 133101211223 in words is "one hundred thirty-three billion, one hundred one million, two hundred eleven thousand, two hundred twenty-three".