Base | Representation |
---|---|
bin | 1100000110110000000110… |
… | …1101000100101010011100 |
3 | 1202010102210000000211120120 |
4 | 3001230001231010222130 |
5 | 3221033122323234400 |
6 | 44150331302514540 |
7 | 2542424325231300 |
oct | 301540155045234 |
9 | 52112700024516 |
10 | 13310132243100 |
11 | 4271882725220 |
12 | 15ab714435a50 |
13 | 7571a89c6c34 |
14 | 3402dcab1d00 |
15 | 181361626ca0 |
hex | c1b01b44a9c |
13310132243100 has 216 divisors, whose sum is σ = 48870657577728. Its totient is φ = 2765741731200.
The previous prime is 13310132243027. The next prime is 13310132243101. The reversal of 13310132243100 is 134223101331.
It is a super-2 number, since 2×133101322431002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13310132243101) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 40995172 + ... + 41318571.
Almost surely, 213310132243100 is an apocalyptic number.
13310132243100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13310132243100 is an abundant number, since it is smaller than the sum of its proper divisors (35560525334628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13310132243100 is a wasteful number, since it uses less digits than its factorization.
13310132243100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82313785 (or 82313771 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13310132243100 its reverse (134223101331), we get a palindrome (13444355344431).
The spelling of 13310132243100 in words is "thirteen trillion, three hundred ten billion, one hundred thirty-two million, two hundred forty-three thousand, one hundred".
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