1331020013 has 4 divisors (see below), whose sum is σ = 1331112000. Its totient is φ = 1330928028.

The previous prime is 1331020001. The next prime is 1331020027. The reversal of 1331020013 is 3100201331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1331020013 - 2¹⁶ = 1330954477 is a prime.

It is a super-2 number, since 2×1331020013² = 3543228550013040338, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1331020013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331020513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19013 + ... + 54986.

It is an arithmetic number, because the mean of its divisors is an integer number (332778000).

Almost surely, 2^1331020013 is an apocalyptic number.

It is an amenable number.

1331020013 is a deficient number, since it is larger than the sum of its proper divisors (91987).

1331020013 is an equidigital number, since it uses as much as digits as its factorization.

1331020013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91986.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 1331020013 is about 36483.1469722665. The cubic root of 1331020013 is about 1100.0055131955.

Adding to 1331020013 its reverse (3100201331), we get a palindrome (4431221344).

The spelling of 1331020013 in words is "one billion, three hundred thirty-one million, twenty thousand, thirteen".