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13310211111 = 34436737037
BaseRepresentation
bin11000110010101100…
…11011010000100111
31021100121111210002220
430121112123100213
5204224403223421
610040432003423
7650560633131
oct143126332047
937317453086
1013310211111
1157102a367a
1226b5690573
131341736482
14903a3a051
1552d7cb3c6
hex31959b427

13310211111 has 4 divisors (see below), whose sum is σ = 17746948152. Its totient is φ = 8873474072.

The previous prime is 13310211097. The next prime is 13310211137. The reversal of 13310211111 is 11111201331.

13310211111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13310211111 - 27 = 13310210983 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310211311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218368516 + ... + 2218368521.

It is an arithmetic number, because the mean of its divisors is an integer number (4436737038).

Almost surely, 213310211111 is an apocalyptic number.

13310211111 is a deficient number, since it is larger than the sum of its proper divisors (4436737041).

13310211111 is an equidigital number, since it uses as much as digits as its factorization.

13310211111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4436737040.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 13310211111 its reverse (11111201331), we get a palindrome (24421412442).

The spelling of 13310211111 in words is "thirteen billion, three hundred ten million, two hundred eleven thousand, one hundred eleven".

Divisors: 1 3 4436737037 13310211111