Base | Representation |
---|---|
bin | 111101111110110000… |
… | …0111110111110011001 |
3 | 110201120010110110122212 |
4 | 1323331200332332121 |
5 | 4140043142113311 |
6 | 141051340124505 |
7 | 12421253614631 |
oct | 1737540767631 |
9 | 421503413585 |
10 | 133102301081 |
11 | 514a2862922 |
12 | 21967836735 |
13 | c722827049 |
14 | 66295016c1 |
15 | 36e03b3c8b |
hex | 1efd83ef99 |
133102301081 has 2 divisors, whose sum is σ = 133102301082. Its totient is φ = 133102301080.
The previous prime is 133102301077. The next prime is 133102301083. The reversal of 133102301081 is 180103201331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88530646681 + 44571654400 = 297541^2 + 211120^2 .
It is a cyclic number.
It is not a de Polignac number, because 133102301081 - 22 = 133102301077 is a prime.
It is a super-2 number, since 2×1331023010812 (a number of 23 digits) contains 22 as substring.
Together with 133102301083, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133102301083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66551150540 + 66551150541.
It is an arithmetic number, because the mean of its divisors is an integer number (66551150541).
Almost surely, 2133102301081 is an apocalyptic number.
It is an amenable number.
133102301081 is a deficient number, since it is larger than the sum of its proper divisors (1).
133102301081 is an equidigital number, since it uses as much as digits as its factorization.
133102301081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
The spelling of 133102301081 in words is "one hundred thirty-three billion, one hundred two million, three hundred one thousand, eighty-one".
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