Base | Representation |
---|---|
bin | 111101111110110000… |
… | …1011101000101101111 |
3 | 110201120010200201212101 |
4 | 1323331201131011233 |
5 | 4140043210040211 |
6 | 141051342515531 |
7 | 12421254640354 |
oct | 1737541350557 |
9 | 421503621771 |
10 | 133102424431 |
11 | 514a2937569 |
12 | 21967895ba7 |
13 | c72286b232 |
14 | 662953462b |
15 | 36e03da5c1 |
hex | 1efd85d16f |
133102424431 has 2 divisors, whose sum is σ = 133102424432. Its totient is φ = 133102424430.
The previous prime is 133102424407. The next prime is 133102424467. The reversal of 133102424431 is 134424201331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133102424431 is a prime.
It is a super-2 number, since 2×1331024244312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133102424431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133102424401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66551212215 + 66551212216.
It is an arithmetic number, because the mean of its divisors is an integer number (66551212216).
Almost surely, 2133102424431 is an apocalyptic number.
133102424431 is a deficient number, since it is larger than the sum of its proper divisors (1).
133102424431 is an equidigital number, since it uses as much as digits as its factorization.
133102424431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 133102424431 its reverse (134424201331), we get a palindrome (267526625762).
The spelling of 133102424431 in words is "one hundred thirty-three billion, one hundred two million, four hundred twenty-four thousand, four hundred thirty-one".
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