Base | Representation |
---|---|
bin | 10011010111100111001… |
… | …110110011111101101110 |
3 | 11201020121101001220120001 |
4 | 103113213032303331232 |
5 | 133301414211023342 |
6 | 2455244130214514 |
7 | 165110010666151 |
oct | 23274716637556 |
9 | 4636541056501 |
10 | 1331024314222 |
11 | 4735365866a9 |
12 | 195b6542443a |
13 | 98690760715 |
14 | 485c9a6dc98 |
15 | 249529348b7 |
hex | 135e73b3f6e |
1331024314222 has 4 divisors (see below), whose sum is σ = 1996536471336. Its totient is φ = 665512157110.
The previous prime is 1331024314219. The next prime is 1331024314241. The reversal of 1331024314222 is 2224134201331.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332756078554 + ... + 332756078557.
It is an arithmetic number, because the mean of its divisors is an integer number (499134117834).
Almost surely, 21331024314222 is an apocalyptic number.
1331024314222 is a deficient number, since it is larger than the sum of its proper divisors (665512157114).
1331024314222 is an equidigital number, since it uses as much as digits as its factorization.
1331024314222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665512157113.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1331024314222 its reverse (2224134201331), we get a palindrome (3555158515553).
The spelling of 1331024314222 in words is "one trillion, three hundred thirty-one billion, twenty-four million, three hundred fourteen thousand, two hundred twenty-two".
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